concurrent assignment to a non net 'q' is not permitted

Concurrent assignment to a non-net q is not permitted

Indrayudh Nandy's profile photo

Indrayudh Nandy

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Richard Damon

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concurrent assignment to a non net 'q' is not permitted

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1165930_001_vivado_Ndvw69km4w.png

  • `timescale 1ns / 1ps
  • //////////////////////////////////////////////////////////////////////////////////
  • // Company:
  • // Engineer:
  • // Create Date: 2020/10/26 10:46:51
  • // Design Name:
  • // Module Name: top
  • // Project Name:
  • // Target Devices:
  • // Tool Versions:
  • // Description:
  • // Dependencies:
  • // Revision:
  • // Revision 0.01 - File Created
  • // Additional Comments:
  • module top(
  • reg[7:0] a;
  • reg[7:0] b;
  • always@*begin
  • son son1(.a(a),.b(b));
  • // Create Date: 2020/10/26 10:48:39
  • // Module Name: son
  • module son(
  • //input clk,
  • input [7:0]a,
  • output reg[7:0]b
  • reg [7:0] aa;
  • reg [7:0] bb;
  • bb = aa\+1;

concurrent assignment to a non net 'q' is not permitted

yangc (AMD)

  • reg [ 7 : 0 ] b ;
  • wire [ 7 : 0 ] b ;

drsdrb (Member)

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IMAGES

  1. 【FPGA】[VRFC 10-3236] concurrent assignment to a non-net ‘data_out’ is

    concurrent assignment to a non net 'q' is not permitted

  2. Concurrent assignment or output port connection should be a net type (2 Solutions!!)

    concurrent assignment to a non net 'q' is not permitted

  3. Verilog Tips 1:TestBench编写注意事项【concurrent assignment to a non-net ‘xxxx

    concurrent assignment to a non net 'q' is not permitted

  4. PPT

    concurrent assignment to a non net 'q' is not permitted

  5. PPT

    concurrent assignment to a non net 'q' is not permitted

  6. PPT

    concurrent assignment to a non net 'q' is not permitted

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COMMENTS

  1. Concurrent assignment to a non-net '_' is not permitted

    The trailing comma in a port list is illegal. Change: output wire c, to: output wire c. It is illegal to assign a value to an input port inside a module. This is illegal: a=1'b1. Assuming it was a typo to use a there, and you really meant to type c, you should change: assign c=(a>b)?(a=1'b1):(c=1'b0);

  2. Concurrent assignment to a non-net is not permitted

    Concurrent assignment to a non-net is not permitted. Ask Question Asked 6 years, 2 months ago. Modified 2 years, 1 month ago. Viewed 28k times 1 I'm making module that make results according to cmd using 4 32-bit adder. if cmd is 0, dout0 = a0+b0, and other dout is zero if cmd is 1, dout1 = a1+b1 and other dout is zero. if cmd is 2 or 3 ...

  3. Error message [VRFC 10-529] concurrent assignment to a non-net P is not

    Another thing to note is when instantiating verilog primitives, the portmapped signals which are used should be of net datatype. I tried this test case with above declaration and able to simulate it properly with expected output P[0] from AND gate.

  4. help me solve concurrent assignment error in verilog for the code given

    Module puts need to be connected to a net-type (ex wire). However a wire cannot be assigned in a procedural code (ex always block). So you need to think how to assign some bits to from a module and other from procedural. \$\endgroup\$

  5. concurrent assignment to a non-net s1 is not permitted

    Please include at least the portlist definition for sub-module Mul_demul. My guess is on this sub-module, port "s1" is an output. Or since you're using port connection by position, instead of port connection by name, and you're connecting up to the wrong ports.

  6. xilinx

    ERROR:HDLCompiler:329 - "tb.v" Line 29. Concurrent assignment to a non-net a is not permitted . ERROR:Simulator:778 - Static elaboration of top level Verilog design unit(s) in library work failed. How can I resolve it ? Thank you

  7. Concurrent assignment or output port connection should be a net type

    You cannot drive a reg type via a continuous assignment (only a wire may be driven in this way).. If this is just modelling combinatorial logic, you could use a combinatorial always block: always @* begin mem[in_d0_] = in_d1_; end

  8. Concurrent assignment to a non-net '_' is not permitted

    March 2, 2023 at 11:55 am. In the ex1 module, you are trying to make a concurrent assignment to a non-net variable 'a' and 'b'. Non-net variables are not allowed to be used in concurrent assignments. You should use 'wire' instead of 'reg' for 'a' and 'b'. Also, the ternary operator should be modified to assign the value ...

  9. Concurrent assignment to a non-net q is not permitted

    Concurrent assignment to a non-net q is not permitted. 290 views. Skip to first unread message ...

  10. Verilog real number assignment error in Vivado

    the continuous assign you are using is only allowed on "net" types (section 6.1.2 of 1364.2001). Real is a reg type (section 3.9 of the same) so I think Vivado is right not to allow it. Try always @* c_real = a_real \+ b_real; which for all practical purposes implements the same logic.

  11. [Solved] Concurrent assignment to a non-net '_' is not permitted

    Dec 23, 2021. #1. qqwetrt8 Asks: Concurrent assignment to a non-net '_' is not permitted. I'm getting the error: Code: concurrent assignment to a non-net 'A' is not permitted. concurrent assignment to a non-net 'B' is not permitted. Static elaboration of top level Verilog design unit(s) in library work failed.

  12. verilog

    The types reg, wire only apply in the current module and are not carried over port connections. Remember the choice of wire or reg is for the simulator not indicative of the hardware. In SystemVerilog the majority of wire/reg can be replaced with logic. The only place this does not work is for tristate busses then you should use tri.

  13. vivado仿真报错:concurrent assignment to a non-net out is not permitted

    一个案例: 待测试模块输入输出为: TestBench测试文件为: 一仿真,报错 concurrent assignment to a non-net 'xxxx' is not permitted 原因分析: 对于待测试模块的输出 "dout_7888",在编写测试文件的时候,不能将与之交联的"dout_7888"定义为 reg 型,须改为 wire 型。 对于模块中的输出来说 即,不能以 TestBench ...

  14. vivado仿真报错:concurrent assignment to a non-net led is not permitted

    一个案例: 待测试模块输入输出为: TestBench测试文件为: 一仿真,报错 concurrent assignment to a non-net 'xxxx' is not permitted 原因分析: 对于待测试模块的输出 "dout_7888",在编写测试文件的时候,不能将与之交联的"dout_7888"定义为 reg 型,须改为 wire 型。 对于模块中的输出来说 即,不能以 TestBench ...

  15. Verilog Tips 1:TestBench编写注意事项【concurrent assignment to a non-net 'xxxx

    文章浏览阅读2.2w次,点赞17次,收藏53次。一个案例:待测试模块输入输出为:TestBench测试文件为:一仿真,报错 concurrent assignment to a non-net 'xxxx' is not permitted原因分析:对于待测试模块的输出 "dout_7888",在编写测试文件的时候,不能将与之交联的"dout_7888"定义为 reg 型,须改为 wire 型。

  16. verilog

    Concurrent assignment to a non-net is not permitted. 0. Verilog HDL error: Illegal left-hand side assignment. 0. ... What is "concurrent assignment to a non-net <port_name> is not permitted" Verilog simulation error? Hot Network Questions How will hitting the gym trigger the effect of the drug?

  17. Error: HDL-Complier-661 Non-net port cannot be mode of input

    You've declared your port as input [3:0] small_mant; - this means you are declaring an input to the module, which must be of a net type (a.k.a. a wire).. However you then re-declare your input port as reg [3:0] small_mant; which is a variable data type (reg), and therefore not a net type.. You cannot, and in fact never need to, declare an input as a reg, so simply remove that line.

  18. 【FPGA】[VRFC 10-3236] concurrent assignment to a non-net 'data_out' is

    一个案例: 待测试模块输入输出为: TestBench测试文件为: 一仿真,报错 concurrent assignment to a non-net 'xxxx' is not permitted 原因分析: 对于待测试模块的输出 "dout_7888",在编写测试文件的时候,不能将与之交联的"dout_7888"定义为 reg 型,须改为 wire 型。 对于模块中的输出来说 即,不能以 TestBench ...

  19. Error "procedural assignment to a non-register result is not permitted"

    Synchronous logic should use non-blocking (<=) assignments. It is legal syntax to blocking (=) assignments in synchronous logic blocks, but is it not recommenced. Using blocking assignments in synchronous logic blocks may cause race conditions in the simulator resulting in behavioral mismatch between RTL and synthesized circuit.

  20. 顶层模块调用子模块仿真出错:[VRFC 10-3236] concurrent assignment to a non-net 'b' is

    谢谢,按照您的方法sim已经不报错了,但是仿真界面的值都是不定态,修改时序后,有了新的错误,我会继续开一个新帖子。