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Eureka Math Grade 3 Module 7 Lesson 23 Answer Key

Engage ny eureka math 3rd grade module 7 lesson 23 answer key, eureka math grade 3 module 7 lesson 23 sprint answer key.

Question 2. 3 × 5 = Answer: 3 × 5 = 15.

Question 3. 4 × 5 = Answer: 4 × 5 = 20.

Question 4. 5 × 5 = Answer: 5 × 5 = 25.

Question 5. 1 × 5 = Answer: 1 × 5 = 5.

Question 6. 10 ÷ 5 = Answer: 10 ÷ 5 = 2.

Question 7. 15 ÷ 5 = Answer: 15 ÷ 5 = 3.

Question 8. 25 ÷ 5 = Answer: 25 ÷ 5 = 5.

Question 9. 5 ÷ 5 = Answer: 5 ÷ 5 = 1.

Question 10. 20 ÷ 5 = Answer: 20 ÷ 5 = 4.

Question 11. 6 × 5 = Answer: 6 × 5 = 30.

Question 12. 7 × 5 = Answer: 7 × 5 = 35.

Question 13. 8 × 5 = Answer: 8 × 5 = 40.

Question 14. 9 × 5 = Answer: 9 × 5 = 45.

Question 15. 10 × 5 = Answer: 10 × 5 = 50.

Question 16. 40 ÷ 5 = Answer: 40 ÷ 5 = 8.

Question 17. 35 ÷ 5 = Answer: 35 ÷ 5 = 7.

Question 18. 45 ÷ 5 = Answer: 45 ÷ 5 = 9.

Question 19. 30 ÷ 5 = Answer: 30 ÷ 5 = 6.

Question 20. 50 ÷ 5 = Answer: 50 ÷ 5 = 10.

Question 21. ___ × 5 = 25 Answer: 5 × 5 = 25.

Question 22. ___ × 5 = 5 Answer: 1 × 5 = 5.

Question 23. ___ × 5 = 50 Answer: 10 × 5 = 50.

Question 24. ___ × 5 = 10 Answer: 2 × 5 = 10.

Question 25. ___ × 5 = 15 Answer: 3 × 5 = 15.

Question 26. 50 ÷ 5 = Answer: 50 ÷ 5 = 10.

Question 27. 25 ÷ 5 = Answer: 25 ÷ 5 = 5.

Question 28. 5 ÷ 5 = Answer: 5 ÷ 5 = 1.

Question 29. 10 ÷ 5 = Answer: 10 ÷ 5 = 2.

Question 30. 15 ÷ 5 = Answer: 15 ÷ 5 = 3.

Question 31. ___ × 5 = 30 Answer: 6 × 5 = 30.

Question 32. ___ × 5 = 35 Answer: 7 × 5 = 35.

Question 33. ___ × 5 = 45 Answer: 9 × 5 = 45.

Question 34. ___ × 5 = 40 Answer: 8 × 5 = 40.

Question 35. 35 ÷ 5 = Answer: 35 ÷ 5 = 7.

Question 36. 45 ÷ 5 = Answer: 45 ÷ 5 = 9.

Question 37. 30 ÷ 5 = Answer: 30 ÷ 5 = 6.

Question 38. 40 ÷ 5 = Answer: 40 ÷ 5 = 8.

Question 39. 11 × 5 = Answer: 11 × 5 = 55.

Question 40. 55 ÷ 5 = Answer: 55 ÷ 5 = 11.

Question 41. 15 ÷ 5 = Answer: 15 ÷ 5 = 3.

Question 42. 60 ÷ 5 = Answer: 60 ÷ 5 = 12.

Question 43. 12 × 5 = Answer: 12 × 5 = 60.

Question 44. 70 ÷ 5 = Answer: 70 ÷ 5 = 14.

Question 2. 2 × 5 = Answer: 2 × 5 = 10.

Question 3. 3 × 5 = Answer: 3 × 5 = 15.

Question 4. 4 × 5 = Answer: 4 × 5 = 20.

Question 5. 5 × 5 = Answer: 5 × 5 = 25.

Question 6. 15 ÷ 5 = Answer: 15 ÷ 5 = 3.

Question 7. 10 ÷ 5 = Answer: 10 ÷ 5 = 2.

Question 8. 20 ÷ 5 = Answer: 20 ÷ 5 = 4.

Question 10. 25 ÷ 5 = Answer: 25 ÷ 5 = 5.

Question 11. 10 × 5 = Answer: 10 × 5 = 50.

Question 12. 6 × 5 = Answer: 6 × 5 = 30.

Question 13. 7 × 5 = Answer: 7 × 5 = 35.

Question 14. 8 × 5 = Answer: 8 × 5 = 40.

Question 15. 9 × 5 = Answer: 9 × 5 = 45.

Question 16. 35 ÷ 5 = Answer: 35 ÷ 5 = 7.

Question 17. 30 ÷ 5 = Answer: 30 ÷ 5 = 6.

Question 18. 40 ÷ 5 = Answer: 40 ÷ 5 = 8.

Question 19. 50 ÷ 5 = Answer: 50 ÷ 5 = 10.

Question 20. 45 ÷ 5 = Answer: 45 ÷ 5 = 9.

Question 21. ___ × 5 = 5 Answer: 1 × 5 = 5.

Question 22. ___ × 5 = 25 Answer: 5 × 5 = 25.

Question 23. ___ × 5 = 10 Answer: 2 × 5 = 10.

Question 24. ___ × 5 = 50 Answer: 10 × 5 = 50.

Question 26. 10 ÷ 5 = Answer: 10 ÷ 5 = 50.

Question 27. 5 ÷ 5 = Answer:

Question 28. 50 ÷ 5 = Answer:

Question 29. 25 ÷ 5 = Answer:

Question 30. 15 ÷ 5 = Answer:

Question 31. ___ × 5 = 15 Answer:

Question 32. ___ × 5 = 20 Answer:

Question 33. ___ × 5 = 45 Answer:

Question 34. ___ × 5 = 35 Answer:

Question 35. 40 ÷ 5 = Answer:

Question 36. 45 ÷ 5 = Answer:

Question 37. 30 ÷ 5 = Answer:

Question 38. 35 ÷ 5 = Answer:

Question 39. 11 × 5 = Answer:

Question 40. 55 ÷ 5 = Answer:

Question 41. 12 × 5 = Answer:

Question 42. 60 ÷ 5 = Answer:

Question 43. 13 × 5 = Answer:

Question 44. 65 ÷ 5 = Answer:

Eureka Math Grade 3 Module 7 Lesson 23 Problem Set Answer Key

Explanation: Perimeter of Gale a miniature stop sign, a regular octagon = 48 centimeters Number of sides of Gale a miniature stop sign, a regular octagon = 8 The length of each side of the stop sign = Perimeter of Gale a miniature stop sign, a regular octagon  ÷ Number of sides of Gale a miniature stop sign, a regular octagon = 48 centimeters ÷  8 = 6 centimeters.

Question 2. Travis bends wire to make rectangles. Each rectangle measures 34 inches by 12 inches. What is the total length of the wire needed for two rectangles? Answer: The total length of the wire needed for two rectangles = 184 inches.

Explanation: Length of the Travis’s rectangle = 34 inches Width of the Travis’s rectangle = 12 inches Perimeter of the Travis’s rectangle = 2 ( Length + Width) = 2 ( 34 inches + 12 inches ) = 2 × 46 inches = 92 inches. The total length of the wire needed for two rectangles = 2 ×  Perimeter of the Travis’s rectangle = 2 ×  92 inches = 184 inches.

Question 3. The perimeter of a rectangular bathroom is 32 feet. The width of the room is 8 feet. What is the length of the room? Answer: The length of the room = 8 feet.

Explanation: Perimeter of a rectangular bathroom = 32 feet. Width of a rectangular bathroom = 8 feet. Length of a rectangular bathroom = ?? Perimeter of a rectangular bathroom = 2 ( Length + Width) => 32 feet = (2 × Length) + (2 × 8 feet) => 32 feet = (2 × Length) + 16 feet => 32 feet – 16 feet = (2 × Length) => 16 feet = (2 × Length) => 16 feet ÷ 2 = Length => 8 feet = Length

Question 5. Mischa makes a 4-foot by 6-foot rectangular banner. She puts ribbon around the outside edges. The ribbon costs $2 per foot. What is the total cost of the ribbon? Answer: Total cost of the ribbon = $20.

Explanation: Length of the rectangular banner = 6-foot Width of the rectangular banner = 4-foot Perimeter of the rectangular banner = 2 ( Length + Width) = 2 ( 6-foot + 4-foot ) = 2 × 10-foot = 20- foot. Cost of the ribbon per foot = $2 Total cost of the ribbon = Perimeter of the rectangular banner × Cost of the ribbon per foot = 20- foot × $2 = $40.

Question 6. Colton buys a roll of wire fencing that is 120 yards long. He uses it to fence in his 18-yard by 24-yard rectangular garden. Will Colton have enough wire fencing left over to fence in a 6-yard by 8-yard rectangular play space for his pet rabbit? Answer: Yes, Colton has wire fencing left over to fence for rectangular play space for his pet rabbit.

Explanation: Total length of wire Colton purchased = 120 yards. Length of the rectangular garden = 24-yard Width of the rectangular garden = 18-yard Perimeter of the rectangular garden = 2 ( Length + Width) = 2 ( 24-yard + 18-yard ) = 2 × 42-yard = 84-yard. Wire used = Total length of wire Colton purchased – Perimeter of the rectangular garden = 120 yards – 84 yards = 36 yards. Length of the rectangular play space for his pet rabbit = 8-yard Width of the rectangular play space for his pet rabbit = 6-yard Perimeter of the rectangular play space for his pet rabbit = 2 ( Length + Width) = 2 ( 8-yard + 6-yard ) = 2 × 14-yard = 28-yard. Wire left = Wire used – Perimeter of the rectangular play space for his pet rabbit = 36 yards – 28 yards = 8 yards.

Eureka Math Grade 3 Module 7 Lesson 23 Exit Ticket Answer Key

Eureka Math Grade 3 Module 7 Lesson 23 Homework Answer Key

Question 1. Rosie draws a square with a perimeter of 36 inches. What are the side lengths of the square? Answer: The side lengths of the square = 9 inches.

Explanation: Perimeter of the Square = 36 inches Number of sides in the square = 4 The side lengths of the square = Perimeter of the Square  ÷ Number of sides in the square = 36 inches ÷ 4 = 9 inches.

Question 2. Judith uses craft sticks to make two 24-inch by 12-inch rectangles. What is the total perimeter of the 2 rectangles? Answer: Total perimeter of the 2 rectangles = 144 inches.

Explanation: Length of the rectangle = 24-inch Width of the rectangle = 12-inch Perimeter of the rectangle = 2 ( Length + Width) = 2 ( 24-inch + 12-inch ) = 2 × 36-inch = 72 inches. Total perimeter of the 2 rectangles = Perimeter of the rectangle × 2 = 72 inches × 2 = 144 inches.

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